Alerts & Newsletters

By subscribing, I agree to the Terms of Use and Privacy Policy.

Who Is Tom Sandoval Dating Now?
Getty Images.

Whether you love to hate him (or just hate him), Tom Sandoval’s dating life on Vanderpump Rules has made for some of the most dramatic reality television to ever be on Bravo. And with his affair with his Vanderpump Rules co-star, Raquel Leviss, in 2023, it’s understandable why Bravoholics are curious about Tom’s next move and who he could date next.

Tom, a cast member on Bravo’s Vanderpump Rules, dated his co-star, Kristen Doute, from 2007 to 2013. They broke up in Season 2 after rumors that Kristen had cheated on Tom with their co-star, Jax Taylor, and rumors that Tom had cheated on Kristen with another co-star, Ariana Madix. Both rumors were true, and less than a year after his breakup with Kristen, Tom and Ariana started dating. The two dated from 2014 to 2023 when news broke that Tom had cheated on Ariana with their Vanderpump Rules co-star, Raquel Leviss.

Tom explained the affair in an interview on the “Howie Mandel Does Stuff” podcast in April 2023. “Like many relationships, it felt like it became more of like a best friends, family [thing] — sometimes roommates,” he said. “There were a lot of ways where the relationship was just lacking the intimacy, the connection. We would travel more by ourselves than we would together. I would go to weddings by myself.”

He also claimed that he “still loved” Ariana despite their messy breakup. “I love Ariana. I still love Ariana and I care about her very much so, but we for a while had been sort of having our own lives,” he said. “We were together for nine years. We built a business and we had a house together, we were a brand.”

Now that #Scandoval is over, fans are looking for what happens next. So who is Tom Sandoval dating now? Read on for what we know about Tom Sandoval’s dating life now and if he has a girlfriend post-#Scandoval.

PMC Logo
StyleCaster is a part of Penske Media Corporation. © 2023 SheMedia, LLC. All Rights Reserved.